find the area of the rectangle whose length is 40cm and a diagonal is 41 cm.
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find the area of the rectangle whose length is 40cm and a diagonal is 41 cm.
Step-by-step explanation:
Δ ACD
AB = CD = 40 CM
AD=41 CM
∠ACD = 90° ( RECTANGLE HAS 90° ON ALL THE BOTH SIDES)
Using Pythagoras theorem
AD² = AC² + CD²
AD² - CD² = AC²
(41)² - (40)² = AC²
1681 - 1600 = 81 = AC²
√81 = AC
AC = 9 CM
The area of Rectangle ABCD = 2 (l+b)
40*9 = 360 CM
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