Find the area of the rectangle whose length is 65 cm and width is half of three less than the length.
Answers
Answered by
6
Answer:
The length of a rectangle is one less than 3 times the width."
which means:
L
=
3
w
−
1
So we add up the lengths and the widths and set them
=
to
54
(the perimeter).
w
+
w
+
3
w
−
1
+
3
w
−
1
=
54
8
w
−
2
=
54
8
w
=
56
w=7
We plug that into
L
=
3
w
−
1
:
L
=
3
(
7
)
−
1
L
=
21
−
1
L
=
20
Answered by
2
Answer:
length
=
20
width
=
7
Explanation:
"The length of a rectangle is one less than 3 times the width."
which means:
L
=
3
w
−
1
So we add up the lengths and the widths and set them
=
to
54
(the perimeter).
w
+
w
+
3
w
−
1
+
3
w
−
1
=
54
8
w
−
2
=
54
8
w
=
56
w
=
7
We plug that into
L
=
3
w
−
1
:
L
=
3
(
7
)
−
1
L
=
21
−
1
L
=
20
Please mark as branliest
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