Find the area of the region bounded above by y = x + 6, bounded below by
y = x
2
and bounded on the sides by the lines x = 0 and x = 2
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Answered by
0
Answer:
A=∫
1
3
x
2
dx
A=[
3
x
3
]
1
3
A=(
3
27
−
3
1
)
A=
3
26
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