Find the area of the region under the given curve from 1 to 2. Y = x2 + 8 3x x2
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Answer:
83−2√23
Explanation:
The area of the region bounded by the curve and the x-axis would be ∫10ydx = ∫10√2x+2dx = 23√2(x+1)32]1o
=23√2(232−1)= 83−2√23
83−2√23
Explanation:
The area of the region bounded by the curve and the x-axis would be ∫10ydx = ∫10√2x+2dx = 23√2(x+1)32]1o
=23√2(232−1)= 83−2√23
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