find the area of the rhombus whose diagonals are 8cm 8mm and 6 cm 5mm.
khushi564:
plz give me a ans
Answers
Answered by
4
8m8mm=1000*88=8.8m
6m5mm=1000*65=6.5m
Diagonals of rhombus bisects each other by 90°,
By Pythagoras theorem,
(8.8/2)²+(6.5/2)²=side²
(77.44+42.24)/4=side²
119.69/4=side²
√29.9225=side
m
I hope this will help you.
6m5mm=1000*65=6.5m
Diagonals of rhombus bisects each other by 90°,
By Pythagoras theorem,
(8.8/2)²+(6.5/2)²=side²
(77.44+42.24)/4=side²
119.69/4=side²
√29.9225=side
m
I hope this will help you.
ans is 2860
8.8cm=88mm, 6.5cm,=65mm
(88+65)/2. =2860mm²
Answered by
5
D1 = 8.8 cm, D2 = 6.5 cm
Area of rhombus = D1+D2/2
= 8.8+6.5/2
= 15.3/2 = 7.6 cm square approx
Area of rhombus = D1+D2/2
= 8.8+6.5/2
= 15.3/2 = 7.6 cm square approx
ans is 2860
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