Question

find the area of the rhombus whose diagonals are 8cm 8mm and 6cm 5mm.

Answer 1

8m8mm=1000×88=8.8m
6m5mm=1000×65=6.5m

=>By Using Pythagoras theorem:-

(8.8÷2)²+(6.5÷2)²=side²
(77.44+42.24)/4=side²
119.69÷4=side² Or
29.92m=side

Answer 2

Converting the Values :

8 cm 8 mm = 88 mm

6 cm 5 mm = 65 mm

$\begin{gathered} \\ \\ \end{gathered}$

$\maltese✠ Calculating \: the \: Area :$

$\begin{gathered} \begin{gathered} \qquad \; \longrightarrow \; \; \sf { Area = \dfrac{1}{2} \times D_1 \times D_2 } \\ \\ \\ \end{gathered} \end{gathered}$

$\begin{gathered} \begin{gathered} \qquad \; \longrightarrow \; \; \sf { Area = \dfrac{1}{2} \times 88 \times 65 } \\ \\ \\ \end{gathered} \end{gathered}$

$\begin{gathered} \begin{gathered} \qquad \; \longrightarrow \; \; \sf { Area = \dfrac{1}{2} \times 5720 } \\ \\ \\ \end{gathered} \end{gathered}$

$\begin{gathered} \begin{gathered} \qquad \; \longrightarrow \; \; \sf { Area = \dfrac{5720}{2} } \\ \\ \\ \end{gathered} \end{gathered}$

$\begin{gathered} \begin{gathered} \qquad \; \longrightarrow \; \; \sf { Area = \cancel\dfrac{5720}{2} } \\ \\ \\ \end{gathered} \end{gathered}$

$\begin{gathered} \begin{gathered} \qquad \; \longrightarrow \; \; {\underline{\boxed{\pmb{\sf{ Area = 2860 \; {mm}^{2} }}}}} \; {\green{\bigstar}} \\ \\ \\ \end{gathered} \end{gathered}$

∴ Area of the Rhombus is 2860 mm² or 28.6 cm² .

$\begin{gathered} \\ \qquad{\rule{200pt}{2pt}} \end{gathered} </p><p>$