Question

Find the area of the rhombus whose each side is 5 cm and whose altitude is 4.8 cm. If one of its diagonals is 8 cm long, find the length of the otherdiagonal​

Answer 1

Answer:

Area of rhombus = Base × Height = 21 ×Product of diagonals⇒5×4.8= 21 ×(8×x)⇒24= 21×(8×x)⇒x=6 cm

Answer 2

Since,a rhombus is also a kind of a parallelogram.

Formula of area of rhombus =Base×Altitude

Putting values, we have

Area of rhombus =5×4.8=24

Since, Area of rhombus is 24 cm².

Also,formula for area of rhombus =$\frac{1}{2}×d_1d_2$

Given,Length of one diagonal =$d_1$=8

Let length of other diagonal =$d_2$

After substituting the values, we get

$24=\frac{1}{2}×8×d_2$

$24=4×d_2$

$4×d_2=24$

$d_2=\frac{24}{4}$

$d_2=6$

Hence, length of other diagonal is 6 cm.