Question

find the area of the Rhombus whose one side is equal to the 10 cm and the length of the one diagonal is 12 centimetre​

Answer 1

Answer:

$\large\underline{\underline{\underline\red{\bold{96cm^2}}}}$

$\bf\large\red{Given}\begin{cases}\bf\large\red{10 cm} \\ \bf\large\red{12 CM } \end{cases}$

$\large\underline\textsf{To \:find :- }$

$\bf\underline{find \:the\: area\: of\: the \:Rhombus}$

$\huge\underline\textsf{Explantion:- }$

$\rightarrow\bf a = (side) = 10cm \\ \rightarrow\bf p = (diagonal) = 12cm$

$\boxed{\bf{\red{Using \: Formula}}}$

$\rightarrow\tt\red{ a = \frac{pq}{2 } } \\ \rightarrow\tt\blue {a = \frac{ \sqrt{p {}^{2} + q {}^{2} } }{2} }$

$\tt\underline\purple{Solving \: to \: A}$

$\rightarrow\bf\orange{ a = \frac{1}{2} p \sqrt{4a {}^{2} - p {}^{2} }} \\ \rightarrow\bf\green{ = \frac{1}{2} .12. \sqrt{4.10 {}^{2} - 12 {}^{2} = 96cm {}^{2} } }$

$\large\underline\because\textsf{the area of Rhombus is 96^2}$