find the area of the right angled triangle whose hypotenuse is 13cm long and one of its leg is 12cm long
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Answered by
10
hypotenuse is 13cm and let perpendicular be 12 cm ..
so by using Pythagoras theorem , base is 5 cm
area of triangle = 1/2× base × height
=1/2×5×12
=30 cm^2
MARK MY ANSWER AS BRAINLIEST
so by using Pythagoras theorem , base is 5 cm
area of triangle = 1/2× base × height
=1/2×5×12
=30 cm^2
MARK MY ANSWER AS BRAINLIEST
Answered by
11
Hey!!
#Here is mine answer ::::::::
______________________________
Hypotenuse = 13cm
One leg = 12cm
Using phythagoras theorem
H² = b² + p²
13² = 12² + p²
169 - 144 = p²
25 = p²
P = 5
Area of triangle =
1/2 × b × p
1/2 × 12 × 5
6×5
30cm²
______________________________
-Sahil
#Here is mine answer ::::::::
______________________________
Hypotenuse = 13cm
One leg = 12cm
Using phythagoras theorem
H² = b² + p²
13² = 12² + p²
169 - 144 = p²
25 = p²
P = 5
Area of triangle =
1/2 × b × p
1/2 × 12 × 5
6×5
30cm²
______________________________
-Sahil
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