Find the area of the right angled triangle with hypotenuse 40cm and on of the other two sides of 24cm
Answers
Answered by
3
let that one side be base.
so, by pythagorous theorem
(prependicular)^2 = (hypotenous)^2 - (base)^2
(p)^2 = (40)^2 - (24)^2
(p)^2 = 1600-576
(p)^2 = 1024
p = 32cm
area of right angle triangle = 1/2×base×height
=1/2×24×32
=12×32
= 384cm^2
if it seems to be helpful mark me as brainliest.
so, by pythagorous theorem
(prependicular)^2 = (hypotenous)^2 - (base)^2
(p)^2 = (40)^2 - (24)^2
(p)^2 = 1600-576
(p)^2 = 1024
p = 32cm
area of right angle triangle = 1/2×base×height
=1/2×24×32
=12×32
= 384cm^2
if it seems to be helpful mark me as brainliest.
Answered by
1
Heya friend,
Given that
Hypotenuse = 40cm
One side = 24cm
Solution
Let base = 24cm
P^2 = H^2 - B^2
=> P^2 = (40)^2 - (24)^2
=> P^2 = 1,600 - 576
=> P^2 = 1024
=> P = √1024
=> P = 32cm
Area of a triangle = 1/2 × base × height
= 1/2 × 24 × 32
= 384 cm^2
Thanks
With regards@
Tanisha
Given that
Hypotenuse = 40cm
One side = 24cm
Solution
Let base = 24cm
P^2 = H^2 - B^2
=> P^2 = (40)^2 - (24)^2
=> P^2 = 1,600 - 576
=> P^2 = 1024
=> P = √1024
=> P = 32cm
Area of a triangle = 1/2 × base × height
= 1/2 × 24 × 32
= 384 cm^2
Thanks
With regards@
Tanisha
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