Question

Find the area of the sector of a circle with radius 4cm and angle 30°. Also, find the area of the corresponding major sector [use π=3.14].

Answer 1

Solution:

Let OAPB be the sector.

Area of the major sector = [(360 – θ)/ 360] × πr²

= [(360 – 30)/360] × 3.14 × 4 × 4

➛ (330/360) × 3.14 × 16

➛ 46.05 cm²

➛ 46.1 cm² (approx)

Thanks

Answer 2

Answer:

It seems you said

$\bf{area\:of\:minor\:sector\:circle}$

First of all we should find out area of circle .

Radius , r = 10cm

so, area of circle = πr² = 3.14 × (10)² = 314 cm²

We know,

Area of circle = area of minor sector + area of major sector

∴ area of major sector = area of circle - area of minor sector

= 314 cm² - 100 cm²

= 214 cm²

Hence, area of major sector of circle = 214 cm²