find the area of the sector of circle with radius 14 CM and angle 60 at centre?
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Answered by
1
Answer:
102.573 sq.cm
Step-by-step explanation:
Radius = 14 cm
\theta = 60 ^{\circ}θ=60
∘
Area of sector = \frac{\theta}{360} \times \pi r^2
360
θ
×πr
2
Substitute the value sin the formula.
Area of sector = \frac{60}{360} \times 3.14 \times (14)^2
360
60
×3.14× (14)
2
= \frac{1}{6} \times 3.14 \times (14)^2
6
1
×3.14× (14)
2
= 102.573 cm^2102.573cm
2
Thus the area of sector is 102.573 sq.cm
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