find the area of the semicircle whose diameter is underroot of 1424
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Answer: 560 unit squares.
Step-by-step explanation:
*i'm sry my keyboard doesn't have the under-root symbol so i'm gonna use the word 'undr' to represent the same.*
Diameter=undr1424
Radius= undr1424/2
AREA = (pi * r^2) /2
=(22/7 * (undr1424/2}^2) /2
= (22/7 * 1424/4)/2
= (22/7 * 356)/2
=22*356/7*2
=11*356 /7
=559.42
= 560 unit squares.
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