find the area of the shaded region
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Area of Sector = θ × π 360 × r2 (when θ is in degrees)
Area of Segment = ( θ × π 360 − sin(θ)2 ) × r2 (when θ is in degrees)
L = θ × π180 × r (when θ is in degrees) AND AREA OD SEGMENT = AREA OF SECTOR MINUS AREA OF TRIANGLE
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AREA OF SECTOR IS ∅°/360° x radius
so
A = 60°/360° x 24
= 1/6 x 24
=4
AREA OF TRIANGLE IN THE CIRCLE = 60° SO, ITS AN equilateral triangle
=√3/4 X A^2
= √3/4 X 24^2
=√3/4 X 576
=249.41531629
NOW AREA OF SHADED PART = AREA OF SECTOR - AREA OF TRIANGLE\
= 2 - 249.41531629
=247.41
AREA WILLNOT BE IN MINUS (-) SO
ANSWER====247.41 CM
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