Question

find the area of the shaded region

Answer 1

Given that,

ABC is a triangle

Where

AB=BC=CA=52 unit

Area of triangle ABC = $\frac{\sqrt{3}}{4} * a^{2}$

= $\frac{\sqrt{3}}{4} * 52^{2}$

= (√3*52*13) unit square.

=√3*676

Now,

BDA is right angle triangle,

Area of BDA = $\frac{1}{2} BD*AD \\ \\ = \frac{1}{2} 16*12 \\ \\ =96 square unit$

Area of shaded region = Area of ABC - Area of BDA

= √3*676 - 96

= 1170.866 - 96

= 1074.866 square unit