find the area of the shaded region, enclosed between two concentric circles of radii 7cm and 14cm where AOC= 40°
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Answered by
488
The Area of Major Sector of bigger circle =
360 -theta / 360 × 22/7 × r × r
360- 40 /360 × 22/7 × 14× 14
By solving it you will get answer as,
547.55 cm^2
The Area of major sector of smaller circle =
360- theta / 360 × 22/7 × r × r
360 - 40 /360 ×22/7×7×7
By solving it you will get answer as,
136.88cm^2
The area of shaded region = area of bigger cicles major sector - area of smaller cicles major sector
Area of shaded region = 547.55 - 136.88
= 410.67 cm ^2
Please mark it as brainliest answer if helpful
360 -theta / 360 × 22/7 × r × r
360- 40 /360 × 22/7 × 14× 14
By solving it you will get answer as,
547.55 cm^2
The Area of major sector of smaller circle =
360- theta / 360 × 22/7 × r × r
360 - 40 /360 ×22/7×7×7
By solving it you will get answer as,
136.88cm^2
The area of shaded region = area of bigger cicles major sector - area of smaller cicles major sector
Area of shaded region = 547.55 - 136.88
= 410.67 cm ^2
Please mark it as brainliest answer if helpful
Answered by
53
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