Math, asked by Anonymous, 9 months ago

find the area of the shape below

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Answers

Answered by CeceBisht
0

Answer:

3 \times 3 = 9 \\  \\  \frac{1}{2}  \times b \times h \\  \\  \frac{1}{2}  \times (7 - 3) \times 3  \\  \\ \frac{15}{2}  \\  \\ 7.5 \:  \: ans

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Answered by Viroop
2

Step-by-step explanation:

the area is area of square +area of right angled triangle

let us assume the quad as ABCD

at c draw a line perpendicular which touches the

above lineAB and the angle made by it is 90 the adj angles are 90 the quad is called a square

area of square is s2 where s should be 3 because all sides in squares are equal .

so 3^2+1/2(4)(3) (height is 7-3=4)

9+6=15q

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