find the area of the smaller region bounded by the ellipse 4x^2 + 9y^2=36 and the line 2x + 3y = 6
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You need to write the standard form of ellipse, hence, you need to divide the equation by 36 such that:
x^2/9 + y^2/4 = 1
Hence, the semi-major axis is a=3 and the semi-minor axis is b=2 .
You should know that the radial line from origin to the point (a,b) intercepts the ellipse at (a/sqrt2,b/sqrt2).
Hence, evaluating the coordinates of point of intersection yields (3/sqrt2,2/sqrt2).
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