Question

find the area of the square whose diagonal is 5 root 2 cm

Answer 1

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Answer 2

Let side of square be= a

In ∆ BCD

DB^2 = DC^2 + BC^2

(5√2)^2 = (a)^2 + (a)^2

50 = 2a^2

a^2= 25

a= √25

a= 5

Area of square

= side × side

= 5 × 5

= 25cm^2