Question

Find the area of the square whose side is 3x² - y.
(Hint =Area of square=side square​

Answer 1

Answer:

area of square=side×side

Step-by-step explanation:

side =3x^2-y

(3x^2-y)(3x^2-y)=(3x^2-y)^2

now apply the formula of (a-b)^2

which is a^2-2ab+b^2

so, (3x^)^2+ y^2-2(3x^2)(y)

= 3x^4 + y^2 -6x^2y

here is your answer..hope it helped u

Answer 2

The area of the square is (9x⁴-6x²y+y²).

Given : The side of the square is (3x²-y)

To find : The area of the square.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the area of the square)

Here, we will be using the formula for calculating the area of the square and other algebraic formulas.

Area of a square = (Side)²

So,

Area of the given square :

= (3x²-y)²

= (3x²)² - (2 × 3x² × y) + (y)²

= 9x⁴-6x²y+y²

(This will be considered as the final result.)

Used formula :

• (a-b)² = a²-2ab+b²

Hence, the area of the square is (9x⁴-6x²y+y²).