Question

Find the area of the square with side 4xy
$4x ^{2} y \times 4x ^{2} y$
​

Answer 1

Given :-

• Side of Square = 4xy

To Find :-

• Area of Square

Answer :-

• $\sf{16\ x^{2}\ y^{2}}$

Concept Used :-

$\sf{ \boxed{ \boxed{Area\:of\:Square\:=\:\ (Side)^{2}}}}$

Solution :-

${}$

$\mapsto\sf{Area\:=\:\ (Side)^{2}}$

${}$

$\mapsto\sf{Area\:=\:\ (4xy)^{2}}$

${}$

$\mapsto\sf{Area\:=\:\ 16\ x^{2}\ y^{2}sq.units}$

${}$

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$\huge\sf{ \underline{Related\:points}}$

★$\sf{Area\:is\:the\:surface\:covered\:by\:any\:body }$

★$\sf{It\:is\:always\:measured\:in\:sq.\:unit}$

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Answer 2

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Question}}}}}}}}$

• Find the area of the square with side 4xy

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{solution}}}}}}}}$

$\sf{\bold{\red{\boxed{\boxed{area = side^2}}}}}$

$\sf\implies area = {4xy}^2$

$\sf\implies area = 16x^2y^2$

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$\sf{\bold{\red{\boxed{\boxed{Extra\: information}}}}}$

• all sides of of square are equal
• all angles are of 90 degres
• diagonals bisect at 90 degrees
• diagonals bisect each other

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