Question

find the area of the thin sheeting required for making an open cistern 5 metre long 3 M wide 4 m deep

Answer 1

l=5m
b=3m
h=4m

total surface area = 2(lb+bh+hl)
". =2(5×3+3×4+4×5)
". =2(15+12+20)
". =2×47=>94m^2
total surface area=94m^2



therefore the area of thin sheet required for making an open cistern is 94 meter square


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Answer 2

Answer : 79 m²

Solution :
_________

Given that :

Length = 5 m

Breadth = 3 m

Height = 4 m

As we know that : Total Surface Area of Cuboid

= 2(lh+hb+lb)

=> 2(5×4+3×4+5×3)

=> 2(20+12+15)

=> 2×47

=> 94 m²

Also given that : Cistern is open

Then, Area = Total Surface Area – Area of upper part

=> Area = Total Surface Area–l×b

=> Area = 94–(5×3) = 94–15

=> Area = 79 m²

So, the area will be sheeting will be 79 m²