find the area of the trapezium in the image
Answers
Given
- Trapezium EFGH
- EH → 23 cm
- FG → 35 cm
- EG → 37 cm
- EH ll FG
- EF ⊥ GF
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To Find
- The area of the trapezium
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Solution
We'll first find the height of the trapezium. If we look closely we can find a right-angled triangle in the given trapezium. So, using the Pythagorean Theorem we will find the height.
Pythagorean Theorem → (Base)² + (Height)² = (Hypotenuse)²
Base → 35 cm
Height → x cm
Hypotenuse → 37 cm
Let's find the height step-by-step.
(35)² + (x)² = (37)²
Step 1: Simplify the equation.
→ (35)² + (x)² = (37)²
→ 1225 + x² = 1369
Step 2: Subtract 1225 from both sides of the equation.
→ 1225 + x² - 1225 = 1369 - 1225
→ x² = 144
Step 3: Find the square root of 144
→ x = √144
→ x = 12
∴ The height of the trapezium is 12 cm
With the obtained value of the height of the trapezium, we'll find the area of the trapezium.
Formula to find the Area of Trapezium →
Side₁ → 23 cm
Side₂ → 35 cm
Height → 12 cm
↦
↦
↦
↦
∴ The area of the following trapezium is 348 cm²
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Step-by-step explanation:
Given
Trapezium EFGH
EH → 23 cm
FG → 35 cm
EG → 37 cm
EH ll FG
EF ⊥ GF
_______________________________________
To Find
The area of the trapezium
_______________________________________
Solution
We'll first find the height of the trapezium. If we look closely we can find a right-angled triangle in the given trapezium. So, using the Pythagorean Theorem we will find the height.
Pythagorean Theorem → (Base)² + (Height)² = (Hypotenuse)²
Base → 35 cm
Height → x cm
Hypotenuse → 37 cm
Let's find the height step-by-step.
(35)² + (x)² = (37)²
Step 1: Simplify the equation.
→ (35)² + (x)² = (37)²
→ 1225 + x² = 1369
Step 2: Subtract 1225 from both sides of the equation.
→ 1225 + x² - 1225 = 1369 - 1225
→ x² = 144
Step 3: Find the square root of 144
→ x = √144
→ x = 12
∴ The height of the trapezium is 12 cm
With the obtained value of the height of the trapezium, we'll find the area of the trapezium.
Formula to find the Area of Trapezium →
Side₁ +Side₂/2 ×height
Side₁ → 23 cm
Side₂ → 35 cm
Height → 12 cm
=23+35/2 ×12
= 58/2×12
= 29×12
=348 cm²
∴ The area of the following trapezium is 348 cm²