Question

find the area of the trapezium, lengths whose parallel sides are 35cm and 25cm and the distance between them is 28 cm​

Answer 1

Answer:

840cm²

Step-by-step explanation:

{1/2×(35+25)×28}cm²

=840cm²

Answer 2

Answer:

Step-by-step explanation:

ANSWER:-

Given that:-

• Length whose parallel sides are 35cm
• 25cm is 2nd side
• And the distance between them is 28 cm​

Concept:-

$\sf{Area \ of \ Trapezium = \dfrac{1}{2} \times (a1+a2) \times h$

• Where a1 is the first side
• Where a2 is second
• And h is height

Let's Do!

$\sf{\dfrac{1}{2}(35+25)\times 28}$

$\sf{\dfrac{1}{2}\times 60 \times 28}$

$\sf{30 \times 28}$

$\rm{= 840 \ cm^2}$

So, required answer is 840 cm^2.

Note:-

• Many times, we need to find height.
• In that case, find the height (by Pythagoras, or any other)
• Special eye on units.