Question

find the area of the trapezium whose parallel sides are 12 cm and 22 CM respectively and non-parallel sides are 6cm and 8 cm........ ​

Answer 1

Step-by-step explanation:

Given find the area of the trapezium whose parallel sides are 12 cm and 22 CM respectively and non-parallel sides are 6 cm and 8 cm  

• Now from the parallelogram ABPQ we have
• AD = BP = 6 cm
• AB = DP = 12 cm
• Now PC = DC – DP
•              = 22 – 12
• Or PC = 10 cm
• From triangle PBC,
• S = a + b + c / 2
•   = 8 + 10 + 6 / 2
•  = 24 / 2
• Or s = 12 cm
• Area of triangle PBC = √s(s – a)(s – b) (s – c)
•                                     = √12(12 – 8)(12 – 10)(12 – 6)
•                                   = √12 x 4 x 2 x 6
•                                    = 24 sq cm
• Now area of triangle = ½ x b x h
•                                     = ½ x PC x h
•                24 = ½ x 10 x h
• Or 5h = 24
• Or h = 4.8 cm
• Now Area of trapezium = ½ x (AB + DC) x h
•                                          = ½ (12 + 22)4.8
•                                          = ½ (34) x 4.8
•                                         = 81.6 sq cm

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