Question

Find the area of the trapezium whose parallel sides are 16 cm and 15 cm, and the distance between the parallel sides is 20 cm.


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Answer 1

area of trapezium=h(a+b)/2 here h= 20,a=16,b=15 and so 20(16+15)/2= 10(31)=310 cm^2
area of trapezium =310 cm^2

Answer 2

$\bold{\boxed{HEY!!!}}$


$<B><I>HERE IS YOUR ANSWER :-$


$\underline{GIVEN}$


Parallel sides = 16 cm and 15 cm


Distance between parallel sides i. e. height = 20 cm


$\underline{\:TO\:FIND}$


Area of trapezium = ?


$\underline{SOLUTION}$


We know that


Area of trapezium = 1/2 × sum of parallel sides × height


= 1/2 × ( 15 + 16 ) × 20


= 31 × 10


= 310 cm²





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