find the area of the triangle abc formed by points a(-5,-1),B(3,-5) andC(5,2)
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Step-by-step explanation:formula = 1/2{x1(y2-y3)x2(y3-y1)x3(y1-y2)}
1/2{-5(-5-2)+3[2-(-2)]+5(-1-[-5]}
1/2(35+9+20)
=32 square unit
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