Question

find the area of the triangle defined by the vertices (0,0),(3,0),(2,3)​

Answer 1

Answer:

Ok this answer is

Step-by-step explanation:

area of this triangle.......

area of this triangle.......area of ΔABC=½{0(0-3)+3(3-0)+2(0-0)}

area of this triangle.......area of ΔABC=½{0(0-3)+3(3-0)+2(0-0)}=½×(0+9+0)

area of this triangle.......area of ΔABC=½{0(0-3)+3(3-0)+2(0-0)}=½×(0+9+0)=9×½