Question

Find the area of the triangle formed by the line equation ax + 3y = 12 and axis​

Answer 1

This can be calculated either graphically or algebraically..

Since, the graphical representation of 2x+3y =6 is a straight line.

And the required triangle is formed by this line graph & coordinate axes, ie X axis & Y axis.

So, if we find out the coordinates of all vertices of triangle, we may calculate its area…

if we suppose the triangle is ABC, in which coordinates of right angled vertex B = (0,0)

Vertex C lies on X axis. & vertex A lies in Y axis…

So, on X axis y coordinate = 0 & on Y axis x coordinate = 0

In 2x + 3y = 6

If x = 0, y = 2

& if y= 0, x = 3

Since x = 3 & y = 2

Hence, area ( tri ABC), which is enclosed by both axes & the line graph of 2x > 3y = 6

= 1/2 * Base * height.

= 1/2 * 3 * 2

= 3 sq unit