Question

Find the area of the triangle formed by the points A(2,0), B(6,0) and (4,6).

Answer 1

Answer:

$Area \: of \: \triangle ABC=12 \: square\:units$

Step-by-step explanation:

$Given \: points \\A(2,0),B(6,0)\: and \: C(4,6)$

$Then \: x_{1}=2,y_{1}=0;\\x_{2}=6,y_{2}=0;\\x_{3}=4,y_{3}=6$

$we\: know ,\\Area \: of \: \triangle \\= \frac{1}{2}|x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})|$

$Area \: of \: \triangle ABC \\=\frac{1}{2}|2(0-6)+6(6-0)+4(0-0)|\\=\frac{1}{2}|-12+36+0|\\=\frac{1}{2}|24|\\=\frac{24}{2}\\=12$

Therefore,

$Area \: of \: \triangle ABC=12 \: square\:units$

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Answer 2

The answer is 12 square units