Find the area of the triangle formed by the straight lines 2x - y - 5=0, x - 5y + 11 = 0
and x + y - 1 = 0.
AL=0
Angle between two lines
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Answered by
67
Answer:
Area of Triangle = 9
Step-by-step explanation:
2x - y - 5=0, x - 5y + 11 = 0 and x + y - 1 = 0.
2x - y - 5=0 Eq 1
x - 5y + 11 = 0 Eq 2
x + y - 1 = 0. Eq 3
Eq 1 + Eq 3
3x - 6 = 0
=> x = 2 , y = -1
Eq3 - Eq 2
6y - 12 = 0
=> y = 2 , x = - 1
Eq 1 - 2 * eq 2
9y -27 = 0
=> y = 3 , x =4
Co-ordiantes are ( 2 , - 1 ) , (-1 , 2) , ( 4 , 3)
Area of Triangle
= |(1/2) { 2(2 - 3) + (-1)(3 -(-1) + 4(-1 - 2)}|
= |(1/2){ -2 - 4 - 12}|
= | -9|
= 9
Area of Triangle = 9
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