Question

Find the area of the triangle formed by the vertices (4, 5), (10, 12) and (-3, 2)​

Answer 1

Answer:

let us consider points as:

x1=4 x2=10. X3= (-3)

y1=5. y2= 12 y3=2

Step-by-step explanation:

now by , substituting value in formula:

area of triangle=1/2[x1(y3-y2)+x2(y2 -y1)+X3 (y1-y3)]

ar∆=1/2[4(2-12)+10(12-5)+(-3)(5-2)]

ar∆=1/2[4(-10)+10(7)-3(3)]

ar∆=1/2[-40+70-6]

ar∆=1/2[30-6]

ar∆=1/2[24]

ar∆=12units

Hope this helps!!!

Answer 2

Answer:

11

Step-by-step explanation:

1/2{x1(y3-y2)+x2(y2-y1)+x3(y1-y3)}

1/2{4(2-12)+10(12-5)+-3(5-2)

1/2{4×-10+10×7+-3×3}

1/2{-40+70-9)

1/2(30-9)

1/2(21)

1.05