If the roots of equation x2 + bx +ac=0 are ,
a , ß and roots of the equation x2 + ax + bc = 0 are a, y then the value of a, ß, y respectively
(A) a,b,c
(C) c.ab
(В) Ь,с, а
(D) None of these
Answers
Answered by
0
Step-by-step explanation:
ANSWER
For quadratic equation ax
2
+bx+c=0
Sum of roots =−
a
b
Product of roots =
a
c
Let x
2
+ax+bc=0 have roots α and β:
α+β=−a......................(1)
αβ=bc...................(2)
Let x
2
+bx+ac=0 have roots α and γ:
α+γ=−b..................(3)
αγ=ac..................(4)
Subtracting (3) from (1) ,we get
β−γ=b−a..................(5)
Dividing (2) and (3)
γ
β
=
a
b
.................(6)
From (5) and (6)
β=b,γ=a
From (2)
α.b=bc⇒α=c
Now, equation having other roots is
x
2
−(β+γ)x+βγ=0
x
2
−(a+b)x+ab..................(7)
Since, β=b is the root of x
2
+ax+bc=0
⇒b
2
+ab+bc=0⇒a+b=−c
Putting this in (7)
we get x
2
+cx+ab=0
Answered by
0
Answer:
Option D) None of these
Step-by-step explanation:
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