Question

Find the area of the triangle if the sides are in the ratio 4 :3 :5 and the
perimeter is 96 cm.

Answer 1

Answer:

Let the sides = 4x , 3x , 5x

Therefore,

Perimeter of triangle = Sum of all sides

=> 96 = 4x + 3x + 5x

=> 96 = 12x

=> 96 ÷ 12 = x

=> 8 = x

=> x = 8

First side = 4 × 8 = 32 cm

Second side = 3 × 8 = 24 cm

Third side = 5 × 8 = 40

Step-by-step explanation:

Hope it's helpful to you :) :)

Answer 2

Answer:

404cm^2

Step-by-step explanation:

Consider the sides of the triangle ABC be 4 x, 5 x and 3x

AB=4x,AC=5x and BC=3x

Perimeter =4x+5x+3x=96

12 x=96

x= 96/12

x=8

Sides are BC=3(8)=24cmAB=4(8)=32cm,

AC=5(8)=40cm

(AC) ^2=(AB)^2+(BC)^2[(5x)^2=(3x)^2+(4x)^2]

semi-perimeter of triangle = perimeter/2

                                             =96/2

                                              =48cm

cc. to heron's formula, area of triangle  

48(48−32)(48−40)(48−24)

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  =[404cm]^2

 

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