Question

find the area of the triangle the length of of whose side are 50 cm and 70 cm and 112 CM

Answer 1

Hope u like my process
=====================
Formula to be used ::
=-=-=-=-=-=-=-=-=-=-=-=-=-
Area = ( S(s-a) (s-b) (s-c)) ^-½

Where S = semi perimeter and
a, b, c are length of sides.
______________________

Semi Perimeter = (a +b +c)/2 = (50+70+112)/2

= 232/2 = 116 cm

Area of triangle (A) =
$\sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{116(116 - 50)(116 - 70)(116 - 112)} \\ \\ = \sqrt{116 \times 66 \times 46 \times 4} \\ \\ = \sqrt{1408704} \\ \\ = 1186.88 \: cm^{2}$
_-_-_-_-_-_-_-_-_-_-_-
Hope this is ur required answer
Proud to help you