if the polynomial 6x^4+8x^3+17x^2+21x+7 is divided by 3x^2+4x+1 then r(x)= ax +b. find a and b
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When we divide 6x4 + 8x3 + 17x2 + 21x + 7 by the polynomial 3x2 + 4x + 1, we get
Quetient = 3x2 + 4x + 5
and Remainder = x + 2
Given, remainder = ax + b
On comparing, we get
a = 1 and b = 2
So, the value of a is 1 and b is 2
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