Question

find the area of the triangle two sides of which are 8 cm and 11 cm and the perimeter of 32 CM

Answer 1

I think this is help u..

Answer 2

$8 \sqrt{ {30cm}^{2} }$

Let a=8cm

b=11cm

p=a+b+c=32cm

c=32−a−b=32−8−11=13cm

$= \frac{a+b+c}{2} = \frac{32}{2} = 16$

$Area= \sqrt{s \times(s - a) \times (s - b) \times (s - c) }$

$Area= \sqrt{16 \times(16 - 8) \times (16 - 11) \times (16 - 13)}$

$Area= \sqrt{16×8×5×3}$

$Area= \sqrt{1920} = 8 \sqrt{30}$

Hence the area is 8√30cm²