Question

find the area of the triangle whos e two sides are 18cm and 10cm and perimeter is 42 cm <br />​

Answer 1

Answer:

the 3rd side of the triangle is (42-18-10)cm

=14cm

half of the perimeter s =42/2cm=21,cm

area of the triangle is

√21(21-18)(21-10)(21-14)sqcm

=√21.3.11.7sqcm

=21√11sqcm