Question

Find the area of the triangle whose perimeter is 180 cm and the two sides are 80 and 18.calculate the altitude also

Answer 1

let the triangle be ABC
its sides are a,b,c
if 
p=180
a=80
b=18
then
c=82
semi perimeter(s) = 180/2=90
area=√s(s-a)(s-c)(s-b)=√90(10)(72)(8)=√518400= 720

the area is 720 cm square

area = bh/2=720
let base =82
height=1440/82 = 17.56 cm