Math, asked by nitikarozenninde, 1 year ago

Find the area of the triangle whose perimeter is 180 cm and the two sides are 80 and 18.calculate the altitude also

Answers

Answered by sukeerthi16
34
let the triangle be ABC
its sides are a,b,c
if 
p=180
a=80
b=18
then
c=82
semi perimeter(s) = 180/2=90
area=√s(s-a)(s-c)(s-b)=√90(10)(72)(8)=√518400= 720

the area is 720 cm square

area = bh/2=720
let base =82
height=1440/82 = 17.56 cm
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