Question

find the area of the triangle whose position vectors i​

Answer 1

Answer:

this is your answer

Step-by-step explanation:

Answer. Given Sides of a traingle OA = i^+3j^+2k^ , OB = 2i^-j^+k^ ,and OC = -i^+2j^+3k^ AB = OB - OA = (2i^-j^+k^) - ( i^+3j^+2k^) = i^ -4j^ - k^ AC = OC - OA = ( -i^+2j^+3k^) - ( i^+3j^+2k^) = -2i^ - j^ + k^. Area of a traingle = (1/2) | AB x AC| = (1/2) |-5i^ + j^ - 9k^| = (1/2) √(25 + 1 + 81) = √107 / 2 square units.

Answer 2

Answer:

AC= OC - OA {(-i^+2j^+3k^)-(i^+3j^+2k^) =-2i^-j^+k^=√107/2 square units.AC=OC-OA=(-i^+2j^+3k^)-(i^+3j^+2k^)=-2i^-j^+k^

Step-by-step explanation:

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