find the area of the triangle whose side are in the ratio 3:4:5 and its perimeter is72cm
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Answered by
3
3x +4x+5x =72
12x=72
x=72÷12
x=6
so 3x=3×6=18
4×=4×6=24
5x=5×6=30
answer
12x=72
x=72÷12
x=6
so 3x=3×6=18
4×=4×6=24
5x=5×6=30
answer
ThakurYash:
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Answered by
3
Let the side be 3x,4x and 5x respectively.
Since their perimeter is 72 hence,
3x+4x+5x=72
=>12x=72
=>x=6
3x=18cm
4x=24cm
5x=30cm
Area = 0.5*24*18=12*18=216
Since their perimeter is 72 hence,
3x+4x+5x=72
=>12x=72
=>x=6
3x=18cm
4x=24cm
5x=30cm
Area = 0.5*24*18=12*18=216
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