Find the area of the triangle whose sides are 11m 60m 61m by using heron's formula
sushilkumaragr468:
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By using Herons formula you can find the area of the triangle
Area of the triangle=√s(s-a)(s-b)(s-c)
Let a=11m
b=60m
c=61m
s=(a+b+c)÷2
=(11+60+61)÷2
∴s=66m
=132÷2 = 66m
As I said Area =√s(s-a)(s-b)(s-c)
=√66(66-11)(66-60)(66-61)
=√66×55×6×5
We can take the common factors outside
=√6×11×5×11×6×5
By removing the roots we will get
=6×11×5
=330m²
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acc to Heron's formula,
A=√sxs-axs-bxs-c, where s is the semiperimeter and a,band c are sides.
s= a+b+c /2
s is equal to 11+60+61/2
s = 132/2
s= 66
A=√ 66x66-11x66-60x66-61
A= √66x 55x 6x 5
A= √ 6x11x5x11x6x5
A= 6x11x5
A= 330m²
A=√sxs-axs-bxs-c, where s is the semiperimeter and a,band c are sides.
s= a+b+c /2
s is equal to 11+60+61/2
s = 132/2
s= 66
A=√ 66x66-11x66-60x66-61
A= √66x 55x 6x 5
A= √ 6x11x5x11x6x5
A= 6x11x5
A= 330m²
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