find the area of the triangle whose sides are 13cms 14cms and 15cms.
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Answered by
3
Hello,
we use the formula of Heron:
A=√p×(p-a)×(p-b)×(p-c)
where:
p is the semiperimeter of the triangle, and a,b c are the sides.
we calculate the semiperimeter of the triangle:
p=(a+b+c):2=(13+14+15):2=42:2=21 cm
we calculate the area:
A=√21×(21-13)×(21-14)×(21-15);
=√21×8×7×6=√7056=84 cm²
The area of the triangle is 84 cm².
bye :-)
we use the formula of Heron:
A=√p×(p-a)×(p-b)×(p-c)
where:
p is the semiperimeter of the triangle, and a,b c are the sides.
we calculate the semiperimeter of the triangle:
p=(a+b+c):2=(13+14+15):2=42:2=21 cm
we calculate the area:
A=√21×(21-13)×(21-14)×(21-15);
=√21×8×7×6=√7056=84 cm²
The area of the triangle is 84 cm².
bye :-)
Answered by
0
Answer:
84cm^2
Step-by-step explanation:
Step-by-step explanation:
By heroins formula
We get s=13+14+15/2
S= 42/2 =21
Now area= root of s(s-a)(s-b)(s-c)
Root of 21 (21-13)(21-14)(21-15)
Root of 21 (8)(7)(6)
Root of 21 (366)
Root of 7056
84cm^2 is the area
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