Math, asked by rljangde40758, 11 months ago

find the area of the triangle whose sides are 21 CM 20 cm and 13 cm​

Answers

Answered by ximahe7111
3

Answer:

I hope this is the right answer.

Attachments:
Answered by SerenaBochenek
5

The area is "126 cm²". Further explanation is given below.

Step-by-step explanation:

Given sides are:

a = 21 cm

b = 20 cm

c = 13 cm

As we know,

s = \frac{a+b+c}{2}

On putting the values in the above formula, we get

⇒  s = \frac{21+20+13}{2}

⇒     = \frac{54}{2}

⇒     = 27 cm

Now,

Area of a triangle = \sqrt{s(s-a)(s-b)(s-c)}

On putting the values in the above formula, we get

⇒  Area = \sqrt{27(27-21)(27-20)(27-13)}

⇒           = \sqrt{27(6)(7)(14)}

⇒           = \sqrt{15876}

⇒           = 126 cm²

Learn more:

https://brainly.in/question/8085556

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