find the area of the triangle whose sides are 26 CM 28 CM 30
cm
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a = 26 cm
b = 28 cm
c = 30 cm
S = a+b+c/2
= 26 + 28 + 30/2
= 84/2
= 42 cm
(s-a) = 42 - 26 = 16 cm
s-b = 42 - 28 = 14 cm
s-c = 42 - 30 = 12 cm
Area = √ S (s-a)(s-b)(s-c)
= √42 * 16 * 14 * 12
= √6 * 7 * 2 * 8 * 2 * 7 * 2 * 6
=6 * 7 * 2 √ 8 * 2
= 84 √2*2*2*2
= 84 * 2 * 2
= 336 cm ^ 2
b = 28 cm
c = 30 cm
S = a+b+c/2
= 26 + 28 + 30/2
= 84/2
= 42 cm
(s-a) = 42 - 26 = 16 cm
s-b = 42 - 28 = 14 cm
s-c = 42 - 30 = 12 cm
Area = √ S (s-a)(s-b)(s-c)
= √42 * 16 * 14 * 12
= √6 * 7 * 2 * 8 * 2 * 7 * 2 * 6
=6 * 7 * 2 √ 8 * 2
= 84 √2*2*2*2
= 84 * 2 * 2
= 336 cm ^ 2
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