Question

find the area of the triangle whose sides are 8cm,10cm,&14cm.

Answer 1

area of triangle=
$1 \div 2 \times base \times height$
=0.5×8×14
56cm
I AM NOT SURE BUT HOPE YOU GOT YOUR ANSWER.

Answer 2

Let a = 8, b = 10 and c = 14. Then, s=1/2(a=b=c)=21

 (s- a) =13 (s - b) = 11and (s - c) = 7.

Area =√ s(s−a)(s−b)(s−c)

=‾√ 21×13×11×7= √ 21021   

=144.98 sq.m