Find the area of the triangle whose sizes measure 52 cm 56 cm and 60 cm respectively.
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Let a = 52cm,b = 56cm,C = 60cm
By Heron's formula,
S = 1/2(a+b+c) = 1/2(52+56+60)=1/2(168) = 84cm
S-A = 84-52 = 32cm
S-B = 84-56 = 28cm
S-C = 84-60 = 24cm
Therefore,
area of triangle = Under root s(s-a)(s-b)(s-c)
= under root 84(32)(28)(24)
SOLVE THIS YOU WILL GET YOUR ANSWER
By Heron's formula,
S = 1/2(a+b+c) = 1/2(52+56+60)=1/2(168) = 84cm
S-A = 84-52 = 32cm
S-B = 84-56 = 28cm
S-C = 84-60 = 24cm
Therefore,
area of triangle = Under root s(s-a)(s-b)(s-c)
= under root 84(32)(28)(24)
SOLVE THIS YOU WILL GET YOUR ANSWER
mira71:
Thank you soooo much saniya
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