find the area of the triangle whose verticals are (2,3) (-1,0) (2,-4).plzz answer me fast?
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∵ The area of a triangle is 21/2sq.unit
Step-by-step explanation:
(i) Let A(2,3), B(−1,0) and C(2,−4) are the vertices of △ABC
Area of triangle= 1/2 [x1 (y2 −y3) + x2 (y3 −y1 ) + x3 (y1 −y2)]
Here (x1 ,y1)=(2,3)
(x2 ,y2)=(−1,0)
(x3,y3 )=(2,−4)
∴ area(triangle) = 1/2 [2(0+4) − 1(−4−3) + 2(3−0)]
= 1/2 [8+7+6]
= 21/2sq.unit
∵ The area of a triangle is 21/2sq.unit
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answer is in pic and it is sooo easy
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