Question

Find the area of the triangle whose vertices are (0 0) (3 0) (0 2)

Answer 1

Here's ur answer dear.

According to me , The answer is absolutely right.

It is solved by using the formula of area of area of triangle.

Answer 2

The area of triangle is 3 square units when the vertices of the triangle is (0,0) ,(3,0), (0,2).

Given that,

We have to the coordinates of the triangles as (0,0)(3,0)(0,2)

We have to find the area of the triangle with the coordinates.

We know that,

The area of triangle = 1/2[x₁(y₂-y₃)+x₂(y₃-y₁)+x₃(y₁-y₂)]

Here,

(0,0)=(x₁,y₁)

(3,0)=(x₂,y₂)

(0,2)=(x₃,y₃)

So, by substitution

The area of triangle = 1/2[0(0-2)+3(2-0)+0(0-0)]

The area of triangle = 1/2[0+6+0]

The area of triangle = 1/2×6

The area of triangle = 3

Therefore, The area of triangle is 3 square units when the vertices of the triangle is (0,0) ,(3,0), (0,2).

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