find the area of the triangle whose vertices are, 0,4 & 3,0 with origin
Answers
Answered by
0
by using formula
1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]
1/2[0(0-0)+3(-0)+0(4-0)]
-3/2
1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]
1/2[0(0-0)+3(-0)+0(4-0)]
-3/2
Answered by
2
Vertices are (0,0) (0,4) and(3,0)
Area=1/2×|0(4-0)+0(0-0)+3(0-4)|
=1/2×|-12|
=1/2 × 12
. =6 sq. unit
Area=1/2×|0(4-0)+0(0-0)+3(0-4)|
=1/2×|-12|
=1/2 × 12
. =6 sq. unit
Similar questions